A) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
B) \[{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
C) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}},{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}}O)}_{6}}]}^{3+}}\]
D) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{(e{{n}_{3}})}_{3}}]}^{3+}}\]
Correct Answer: B
Solution :
The order of the ligand in the spectrpcemical series \[{{H}_{2}}O<N{{H}_{3}}<en\] Hence, the wavelength of the light observed will be in the order \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}<{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}<{{[Co{{(en)}_{3}}]}^{3+}}\] Thus, wavelength absorbed will be in the opposite order i.e., \[{{[Co{{(en)}_{3}}]}^{3+}},{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}},{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]You need to login to perform this action.
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