A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{2}{5}\]
D) \[\frac{2}{7}\]
Correct Answer: C
Solution :
Given process is isobaric \[\text{dQ=n}{{\text{C}}_{\text{p}}}\text{dT}\] \[\text{dQ=n}\left( \frac{\text{5}}{\text{2}}\text{R} \right)\text{dT}\] \[\text{dW=PdV=nRdT}\] Required ratio\[\text{=}\frac{\text{dW}}{\text{dQ}}\text{=}\frac{\text{nRdT}}{\text{n}\left( \frac{\text{5}}{\text{2}}\text{R} \right)\text{dT}}\text{=}\frac{\text{2}}{\text{5}}\]You need to login to perform this action.
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