A) \[\frac{7}{5}D\]
B) \[D\]
C) \[\frac{3}{2}D\]
D) \[\frac{5}{4}D\]
Correct Answer: D
Solution :
As track is frictionless, so total mechanical energy will remain constant \[\text{T}\text{.M}\text{.}{{\text{E}}_{\text{l}}}\text{=T}\text{.M}\text{.}{{\text{E}}_{\text{F}}}\] \[\text{0+mgh=}\frac{1}{2}m{{v}_{L}}^{2}+0\] \[h=\frac{v_{L}^{2}}{2g}\] For completing the vertical circle, \[{{v}_{L}}\ge \sqrt{5gR}\] \[h=\frac{5gR}{2g}=\frac{5}{2}R=\frac{5}{4}D\]You need to login to perform this action.
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