A) \[i={{\sin }^{-1}}\left( \frac{1}{\mu } \right)\]
B) Reflected light is polarised with its electric vector perpendicular to the plane of incidence
C) Reflected light is polarised with its electric vector parallel to the plane of incidence
D) \[i={{\tan }^{-1}}\left( \frac{1}{\mu } \right)\]
Correct Answer: B
Solution :
When reflected light rays and refracted rays are perpendicular, reflected light is polarised with electric field vector perpendicular to the plane of incidence. Also, \[\tan \text{ i=}\mu \](Brewster angle)You need to login to perform this action.
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