A) \[\frac{256}{81}\]
B) \[\frac{4}{3}\]
C) \[\frac{3}{4}\]
D) \[\frac{81}{256}\]
Correct Answer: A
Solution :
We know, \[{{\lambda }_{\text{max}}}\text{T=}\]constant (Wien's law) So, \[{{\lambda }_{\text{ma}{{\text{x}}_{\text{1}}}}}{{\text{T}}_{\text{1}}}\text{=}{{\lambda }_{\text{ma}{{\text{x}}_{\text{2}}}}}{{\text{T}}_{\text{2}}}\] \[\Rightarrow {{\lambda }_{0}}T=\frac{3{{\lambda }_{0}}}{4}T'\] \[\Rightarrow T'=\frac{4}{3}T\] So, \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{T'}{T} \right)}^{4}}={{\left( \frac{4}{3} \right)}^{4}}=\frac{256}{81}\]
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