A) 6.25%
B) 20%
C) 26.8%
D) 12.5%
Correct Answer: C
Solution :
Efficiency of ideal heat engine, \[\eta \text{=}\left( \text{1-}\frac{{{\text{T}}_{\text{2}}}}{{{\text{T}}_{\text{1}}}} \right)\] \[{{\text{T}}_{\text{2}}}\]: Sink temperature \[{{\text{T}}_{1}}\]: Source temperature \[%\eta \text{=}\left( \text{1-}\frac{{{\text{T}}_{\text{2}}}}{{{\text{T}}_{\text{1}}}} \right)\text{ }\!\!\times\!\!\text{ 100}\] \[=\left( 1-\frac{273}{373} \right)\times 100\] \[=\left( \frac{100}{373} \right)\times 100=26.8%\]
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