A) Is tripled
B) Is doubled
C) Is halved
D) Remains unchanged
Correct Answer: B
Solution :
Half-life of zero order \[{{t}_{1/2}}=\frac{[{{A}_{0}}]}{2K}\] \[{{t}_{1/2}}=\frac{[{{A}_{0}}]}{2K}\] \[{{t}_{1/2}}\] will be doubled on doubling the initial concentration.You need to login to perform this action.
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