A) \[\frac{\lambda }{\pi {{\in }_{0}}R}N/C\]
B) \[\frac{\lambda }{2\pi {{\in }_{0}}R}N/C\]
C) Zero
D) \[\frac{2\lambda }{\pi {{\in }_{0}}R}N/C\]
Correct Answer: B
Solution :
At \[P,\text{ }E={{E}_{1}}+{{E}_{2}}=\frac{2k{{\lambda }_{1}}}{R}+\frac{2k{{\lambda }_{2}}}{R}\] \[\therefore {{\lambda }_{1}}={{\lambda }_{2}}\] \[\frac{4K\lambda }{R}=\frac{\lambda }{\pi {{\in }_{0}}R}\]You need to login to perform this action.
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