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NEET NEET SOLVED PAPER 2019

  • question_answer
    A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of \[2.5\times {{10}^{2}}\]N/m. The pressure inside the bubble equals at a point \[{{Z}_{0}}\]below the free surface of water in a container. Taking\[g=10\text{ }m/{{s}^{2}}\], density of water\[={{10}^{3}}kg/{{m}^{3}}\], the value of \[{{Z}_{0}}\] is:                         [NEET 5-5-2019]

    A) 1 cm    

    B) 0.5 cm

    C) 100 cm             

    D) 10 cm

    Correct Answer: A

    Solution :

    \[\rho g{{Z}_{0}}=\frac{4T}{R}\] \[{{10}^{3}}.10.{{Z}_{0}}=\frac{4(2.5\times {{10}^{-2}})}{{{10}^{-3}}}\] \[=\frac{100}{{{10}^{4}}}\] \[{{Z}_{0}}={{10}^{-2}}\] \[Z=1cm\]         


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