A) \[0.05{}^\circ \]
B) \[0.1{}^\circ \]
C) \[0.266{}^\circ \]
D) \[0.15{}^\circ \]
Correct Answer: D
Solution :
\[\theta \propto \lambda \] \[{{\lambda }_{1}}=400\text{ }nm,{{\theta }_{1}}=0.2{}^\circ ,{{\mu }_{water}}=4/3\] \[\frac{{{\theta }_{1}}}{{{\theta }_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\mu =\frac{c}{v}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{4}{3}\] \[\frac{{{\theta }_{1}}}{{{\theta }_{2}}}=\frac{4}{3}\] \[{{\theta }_{2}}=\frac{3}{4}({{\theta }_{1}})\] \[=\frac{4}{3}(0.2{}^\circ )=0.15{}^\circ \]
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