NEET NEET SOLVED PAPER 2019

  • question_answer
    Which is the correct thermal stability order for \[{{H}_{2}}E\](E = O, S, Se, Te and Po)? [NEET 5-5-2019]

    A) \[{{H}_{2}}Po<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\]

    B) \[{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po<{{H}_{2}}O<{{H}_{2}}S\]

    C) \[{{H}_{2}}S<{{H}_{2}}O<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]

    D) \[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]

    Correct Answer: A

    Solution :

    As we move downwords stability of Hydrides decreases \[{{H}_{2}}O>{{H}_{2}}S>{{H}_{2}}Se>{{H}_{2}}Te>{{H}_{2}}Po\]


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