A) \[2\times {{10}^{3}}\text{ }V\]
B) 0.02 V
C) 2 V
D) 0.2 V
Correct Answer: B
Solution :
\[emf=\frac{\Delta \phi }{\Delta t}=\frac{BAN}{\Delta t}\] \[=\frac{(5\times {{10}^{5}})(0.05)(8000)}{0.1}\] \[=\frac{200\times {{10}^{-5}}\times {{10}^{-2}}\times {{10}^{2}}}{{{10}^{-1}}}=0.02\,volt\]You need to login to perform this action.
You will be redirected in
3 sec