A) \[\frac{1}{2}Mgl\]
B) \[\frac{1}{2}MgL\]
C) \[Mgl\]
D) \[MgL\]
Correct Answer: A
Solution :
Loss in gravitational P.E. =\[Mgl\] Elastic potential energy \[U=\frac{1}{2}Mgl\]You need to login to perform this action.
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