A) \[{{C}_{3}}{{A}_{4}}\]
B) \[{{C}_{4}}{{A}_{3}}\]
C) \[{{C}_{2}}{{A}_{3}}\]
D) \[{{C}_{3}}{{A}_{2}}\]
Correct Answer: A
Solution :
Solid state C : A 75% O.V. : (HCP) \[6\times \frac{75}{100}\] : 6 \[\frac{3}{4}\] : 1 4 3 : 4 \[{{C}_{3}}{{A}_{4}}\]
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