A) \[{{e}^{3}}t_{2}^{3}\]
B) \[{{e}^{4}}t_{2}^{2}\]
C) \[t_{2g}^{4}e_{g}^{2}\]
D) \[t_{2g}^{6}e_{g}^{0}\]
Correct Answer: D
Solution :
\[{{K}_{4}}\left[ Fe{{(CN)}_{6}} \right]\] has \[F{{e}^{+2}}=\text{ }\!\![\!\!\text{ }Ar\text{ }\!\!]\!\!\text{ }3{{d}^{6}}\]You need to login to perform this action.
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