A) \[100\text{ }mL\text{ }of\text{ }0.1\text{ }M\text{ }HCl+200\text{ }mL\text{ }of\text{ }\] \[0.1M\text{ }N{{H}_{4}}OH\]
B) \[100\text{ }mL\text{ }of\text{ }0.1\text{ }M\text{ }HCl+100\text{ }mL\text{ }of\text{ }\] \[0.1\text{ }M\text{ }NHOH\]
C) \[50\text{ }mL\text{ }of\text{ }0.1\text{ }M\text{ }NaOH+25\text{ }mL\text{ }of\] \[0.1\text{ }M\text{ }C{{H}_{3}}COOH\]
D) \[100\text{ }mL\text{ }of\text{ }0.1\text{ }M\text{ }C{{H}_{3}}COOH+100\] \[mL\text{ }of\text{ }0.1\text{ }M\text{ }NaOH\]
Correct Answer: A
Solution :
Weak Acid > Strong Base Weak Base > Strong Acid \[M\text{ }200\text{ }Ml\text{ }N{{H}_{4}}OH>0.1\text{ }M\text{ }100\text{ }Ml\text{ }HCl\]
You need to login to perform this action.
You will be redirected in
3 sec
