A)
B)
C)
D)
Correct Answer: A
Solution :
\[{{B}_{inside}}=\frac{{{\mu }_{0}}id}{2\pi {{R}^{2}}}\] \[{{B}_{in}}\propto d\] \[{{B}_{out}}=\frac{{{\mu }_{0}}i}{2\pi d}\] \[{{B}_{out}}\propto \frac{1}{d}\]You need to login to perform this action.
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