A) \[280\]
B) \[50\,\,\mu C\]
C) \[100\,\,\mu C\]
D) \[200\,\,\mu C\]
Correct Answer: D
Solution :
Capacitance of first capacitor\[{{C}_{1}}=3\mu F\] Capacitance of second capacitor\[{{C}_{2}}=10\mu F\] Capacitance of third capacitor\[{{C}_{3}}=15\mu F\] Applied potential\[V=100\,\,volt\] Equivalent capacitance when connected in series is given by \[\frac{1}{{{C}_{eq}}}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}=\frac{1}{3}+\frac{1}{10}+\frac{1}{15}=\frac{1}{2}\] Charge on \[15\,\,\mu F\] capacitor \[q=2\times 100=200\,\,\mu C\]
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