A) \[2980\,\,yr\]
B) \[3070\,\,yr\]
C) \[2966\,\,yr\]
D) \[2770\,\,yr\]
Correct Answer: C
Solution :
Here: Initial activity of wood \[({{N}_{0}})=1;\]final activity of wood\[({{N}_{1}})=0.70\]and half-life\[{{t}_{1/2}}=5760\,\,yr\]. We know that disintegration constant \[(\lambda )=\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{5760}\] We also know that \[(t)=\frac{2.303}{k}\log \frac{{{N}_{o}}}{{{N}_{t}}}t=\frac{2.303}{k}.\log \frac{1}{7}\] or\[\frac{2.303\times 5760\times 0.155}{0.693}=2966\,\,yr\].You need to login to perform this action.
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