A) \[{{90}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{30}^{o}}\]
Correct Answer: C
Solution :
The modulus of cross and dot product of vectors \[\overset{\to }{\mathop{A}}\,\] and \[\overset{\to }{\mathop{B}}\,\] is \[AB\sin \theta \] and\[AB\cos \theta \]. Hence, the given condition \[AB\sin \theta =AB\cos \theta \] \[\tan \theta =1=\theta ={{45}^{o}}\]You need to login to perform this action.
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