A) \[4\,\,\mu F\]
B) \[18\,\,\mu F\]
C) \[\frac{28}{9}\,\,\mu F\]
D) \[5\,\,\mu F\]
Correct Answer: D
Solution :
The circuit which is given that can be rearranged as Now the resultant capacitance between \[\mathbf{A}\] and \[\mathbf{B}\] is given by \[{{C}_{AB}}=\frac{4\times 12}{4+12}=2=3+2=5\mu F\]You need to login to perform this action.
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