A) \[1.7\times {{10}^{3}}\text{J}\]
B) \[10.2\times {{10}^{3}}\text{J}\]
C) \[3.4\times {{10}^{3}}\text{J}\]
D) \[6.8\times {{10}^{3}}\text{J}\]
Correct Answer: C
Solution :
According to kinetic theory that \[KE\] of \[1\,\,g-\]mole of an ideal gas,\[E=\frac{3}{2}RT\] Hence, \[KE\] at normal temperature \[{{0}^{o}}C\] \[=273\,\,K\] or \[E=\frac{3}{2}\times 8.31\times 273\] \[=3.4\times {{10}^{3}}\text{J}\]You need to login to perform this action.
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