A) \[100%\]
B) \[90%\]
C) \[35%\]
D) \[70%\]
Correct Answer: D
Solution :
Using the relation for the efficiency of Carnots engine, we have \[\eta =\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)\times 100\] Here: \[{{T}_{2}}=273+27=300\,\,K\] \[{{T}_{1}}=273+727=1000\,\,K\] \[\eta =\left( 1-\frac{300}{1000} \right)\times 100=70%\]You need to login to perform this action.
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