A) \[2.4\times {{10}^{-12}}N\]
B) \[4.8\times {{10}^{-12}}N\]
C) \[1.2\times {{10}^{-12}}N\]
D) \[7.2\times {{10}^{-12}}N\]
Correct Answer: A
Solution :
Here:\[q=1.6\times {{10}^{-19}}C,\,\,B=1.5\,\,wb/{{m}^{2}}\], \[v=2\times {{10}^{7}}m/s,\,\,\theta ={{30}^{o}}\]or\[\sin {{30}^{o}}=\frac{1}{2}\] Force on proton is given by \[F=qv\,\,B\sin \theta \] \[=1.6\times {{10}^{-19}}\times 2\times {{10}^{7}}\times 1.5\times \frac{1}{2}\] \[=2.4\times {{10}^{-12}}N\]You need to login to perform this action.
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