A) \[0.1\Omega \]
B) \[0.2\Omega \]
C) \[0.3\Omega \]
D) \[0.4\Omega \]
Correct Answer: A
Solution :
Here:\[{{I}_{g}}=0.01\,\,A,\,\,G=50\Omega \] To convert the galvanometer in to an ammeter of range of\[5A\], a low resistance is to be connected in parallel with coil of galvanometer. \[S=\frac{ig\times G}{i-{{i}_{g}}}\] \[=\frac{0.01\times 50}{5-0.01}=\frac{0.5}{4.99}\] \[=0.1\,\,\Omega \]You need to login to perform this action.
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