A) \[21\]
B) \[27\]
C) \[38\]
D) \[49\]
Correct Answer: D
Solution :
The equivalent weight of\[{{H}_{3}}P{{O}_{4}}=\frac{molecular\,\,weight}{2}\](molecular wt. of\[{{H}_{3}}P{{O}_{4}}\]\[=3+31+64=98\]) \[=\frac{98}{2}=49\]You need to login to perform this action.
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