A) \[0.2\]
B) \[0.01\]
C) \[0.1\]
D) \[0.3\]
Correct Answer: C
Solution :
Miliequivalents of \[{{H}_{2}}S{{O}_{4}}=100\times 0.2\times 2=40\] Miliequivalents of \[NaOH=100\times 0.2\times 2=40\] Miliequivalents of \[{{H}_{2}}S{{O}_{4}}\] left after neutralization\[=40-20=20\] Total volume of the solution \[=100+100=200ml\] Normality of\[{{H}_{2}}S{{O}_{4}}(left)=\frac{20}{200}=0.1N\]You need to login to perform this action.
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