A) \[400K\]
B) \[4000K\]
C) \[80000K\]
D) \[40000K\]
Correct Answer: C
Solution :
Radiant energy\[E\propto {{T}^{4}}\] \[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\] \[\frac{4.32\times {{10}^{6}}}{2.7\times {{10}^{-3}}}={{\left( \frac{{{T}_{2}}}{127+273} \right)}^{4}}\] \[16\times {{10}^{8}}={{\left( \frac{{{T}_{2}}}{400} \right)}^{4}}\] \[2\times {{10}^{2}}=\frac{{{T}_{2}}}{400}\] \[\therefore \] \[{{T}_{2}}=400\times 2\times {{10}^{2}}\]You need to login to perform this action.
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