A) high temperature and high pressure
B) low temperature and low pressure
C) high temperature and low pressure
D) low temperature and high pressure
Correct Answer: D
Solution :
\[{{N}_{2}}\]and \[{{H}_{2}}\] combine to give ammonia as follows: \[\underset{1\,\,vol}{\mathop{{{N}_{2}}(g)}}\,+\underset{3\,\,vol}{\mathop{3{{H}_{2}}(g)}}\,\underset{2\,\,vol}{\mathop{2N{{H}_{3}}(g)}}\,\] \[\Delta H=-92.38kJ\,\,mo{{l}^{-1}}\] This reaction is exothermic and is accompanied by decrease in volume. So favourable conditions for forward reaction/ according to Le-Chateliers principle are: (i) low temperature (ii) high pressure (iii) excess of \[{{N}_{2}}\] and \[{{H}_{2}}\]
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