A) 4
B) 6
C) 8
D) 10
Correct Answer: D
Solution :
\[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] Given: \[p{{K}_{b}}=5,\,\,[base]=0.10M\] \[[salt]=0.01\,\,M\] \[\therefore \] \[pOH=5+\log \frac{0.01}{0.10}=4\] \[pH+pOH=14\] \[\therefore \] \[pH=14-4=10\]You need to login to perform this action.
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