A) Shrinks
B) Disappear
C) Unchanged
D) Enlarged
Correct Answer: A
Solution :
In Youngs double slit experiment, let screen is placed at a distance\[D\], \[d\] is the distance between coherent sources. The fringe width is given by \[W=\frac{D\lambda }{d}\] where, \[\lambda \] is wavelength of light used. When dipped in water, wavelength is\[{{\lambda }_{\omega }}=\frac{{{\lambda }_{a}}}{\mu },\]hence, it decreases. Therefore, fringe width decreases and hence, fringe pattern shrinks.You need to login to perform this action.
You will be redirected in
3 sec