A) \[4s\]orbital
B) \[4p\]orbital
C) \[4d\]orbital
D) \[4f\]orbital
Correct Answer: C
Solution :
\[n=4\](4th shell) \[l=2\](\[d-\]subshell) \[{{m}_{l}}=-2\](\[{{d}_{xy}}\]orbital) \[s=+\frac{1}{2}(\uparrow )\] ? (i) Hence, electron belongs to \[4d\] orbital.You need to login to perform this action.
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