A) \[N_{2}^{-}\]
B) \[O_{2}^{-}\]
C) \[N_{2}^{2-}\]
D) \[O_{2}^{2-}\]
Correct Answer: A
Solution :
Given, electronic configuration of anion\[X\]is: \[\sigma 1{{s}^{2}},\,\,\sigma *1{{s}^{2}},\,\,\sigma 2{{s}^{2}},\,\,\sigma *2{{s}^{2}},\,\,\sigma 2p_{x}^{2},\,\,\pi 2p_{y}^{2},\,\,\sigma 2p_{z}^{2}\] \[\pi *2p_{x}^{1}\] \[\therefore \]total number of electrons of anion\[X=15\] Hence, the anion \[X\] is\[N_{2}^{-}\].You need to login to perform this action.
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