A) \[1mm\]
B) \[2mm\]
C) \[4mm\]
D) \[8mm\]
Correct Answer: A
Solution :
\[Y=\frac{longitudinal\,\,stress}{longitudinal\,\,strain}\] \[Y=\frac{F/A}{\Delta l/L}\] where \[F\] is force, \[A\]is area, \[\Delta l\]is change is length and \[L\] is original length. First case \[Y=\frac{F/A}{2/L}\] ? (i) Second case \[Y=\frac{F/A}{\Delta l/L/2}\] ? (ii) Equating Eqs. (1) and (2), we get \[\frac{L}{2}=\frac{L/2}{\Delta l}\] \[\Rightarrow \] \[\Delta l=1mm\]You need to login to perform this action.
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