A) fifth group
B) fifteenth group
C) second group
D) third group
Correct Answer: A
Solution :
An atom has electronic configuration\[1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}},\,\,3{{s}^{2}}3{{p}^{6}}3{{d}^{3}},\,\,4{{s}^{2}}\] It is a member of \[d-\]block element because the last electron is filled in \[d-\]subshell as \[3{{d}^{3}}\] and the following electronic configuration is possible for \[d-\]subshell as\[(n-1)\]\[d-\]subshell as\[(n-1){{d}^{1to10}}\]Group No. III | B | IVB | VB | VIB | VIIB | VIII | VIII | VIII | IB | IIB |
(13) | (14) | (15) | (16) | (17) | (18) | (19) | (20) | (21) | (22) | |
\[n{{s}^{2}}(n-1){{s}^{2}}{{p}^{6}}\] | \[{{d}^{1}}\] | \[{{d}^{2}}\] | \[{{d}^{3}}\] | \[{{d}^{4}}\] | \[{{d}^{5}}\] | \[{{d}^{6}}\] | \[{{d}^{7}}\] | \[{{d}^{8}}\] | \[{{d}^{9}}\] | \[{{d}^{10}}\] |
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