A) \[\sqrt{\frac{h}{8g}}\]
B) \[\sqrt{8gh}\]
C) \[\sqrt{2gh}\]
D) \[\sqrt{\left( \frac{h}{2g} \right)}\]
Correct Answer: A
Solution :
For first stone\[v=0\]and For second stone\[\frac{{{v}^{2}}}{2g}=4h\]\[\Rightarrow \]\[{{u}^{2}}=8gh\] \[\therefore \] \[u=\sqrt{8gh}\]You need to login to perform this action.
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