A) \[X\text{--}Y/R\]
B) \[(X-Y)R/Y\]
C) \[(X-Y)Y/R\]
D) \[(X-Y)R\]
Correct Answer: B
Solution :
If \[r\] be the internal resistance of the cell, then the current through the circuit is given by \[l=\frac{E}{(R+r)}\] Substituting\[E=X\], we get \[I=\frac{X}{R+r}\] ? (i) Now, potential difference across the resistor is given by \[V=IR\] Substituting\[V=Y,\,\,I=\frac{X}{R+r}\] [from Eq. (i)] we get \[Y=\frac{XR}{R+r}\] On solving, we get \[r=\frac{(X-Y)R}{Y}\]You need to login to perform this action.
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