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Punjab Medical Punjab - MET Solved Paper-2007

  • question_answer
    In the following common emitter circuit if\[\beta =100\],\[{{V}_{CE}}=7V\],\[{{V}_{BE}}=\]Neglegible,\[{{R}_{C}}=2k\Omega \]then

    A) \[0.01mA\]                        

    B) \[0.04mA\]

    C) \[0.02mA\]                        

    D) \[0.03mA\]

    Correct Answer: B

    Solution :

    \[V={{V}_{CE}}+{{i}_{C}}{{R}_{L}}\] \[\Rightarrow \]               \[15=7+{{i}_{C}}\times 2\times {{10}^{3}}\] \[\Rightarrow \]               \[{{i}_{C}}=4mA\] \[\because \]     \[\beta =\frac{{{i}_{C}}}{{{i}_{B}}}\Rightarrow \,\,\,{{i}_{B}}=\frac{4}{100}=0.04\,\,mA\]


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