A) \[4\,\,mA\]
B) \[2\,\,mA\]
C) \[3.6\,\,mA\]
D) \[1.8\,\,mA\]
Correct Answer: D
Solution :
\[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] \[\therefore \] \[30=\frac{\Delta {{i}_{C}}}{90-30}\] \[\Delta {{i}_{C}}=30\times 60\] \[=1800\mu A=1.8\,\,mA\]You need to login to perform this action.
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