A) 4
B) 2
C) 1
D) 0.5
Correct Answer: B
Solution :
Maximum acceleration = Maximum velocity\[\times \,\,\pi \]ie, \[{{\omega }^{2}}A=\pi \omega A\] where\[A\]is amplitude and \[\omega \] is angular velocity. \[\Rightarrow \] \[\omega =\pi \] \[\Rightarrow \] \[\frac{2\pi }{T}=\pi \] \[\Rightarrow \] \[T=2s\]You need to login to perform this action.
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