A) \[9.6\,\,V\]
B) \[6.6\,\,V\]
C) \[4.8\,\,V\]
D) \[3.2\,\,V\]
Correct Answer: D
Solution :
Potential difference across \[PQ\] ie, potential difference across the resistance of \[20\Omega \] is \[V=i\times 20\] and\[i=\frac{48}{(100+100+80+20)}=0.16A\] \[V=0.16\times 20=3.2volt\]You need to login to perform this action.
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