A) \[6.54cm\]
B) \[3.64cm\]
C) \[1.77cm\]
D) \[0.88cm\]
Correct Answer: C
Solution :
Here mass\[M=50g\]and radius\[R=-2.5cm\]. Required moment of inertia of the disc is given by \[I=\frac{M{{R}^{2}}}{2}=M{{K}^{2}}\] So, \[{{K}^{2}}=\frac{{{R}^{2}}}{2}\] or \[K=\frac{R}{\sqrt{2}}=\frac{2.5}{\sqrt{2}}=\frac{2.5\sqrt{2}}{2}\]You need to login to perform this action.
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