A) \[{{C}_{V}}=\frac{3}{2}R\]for a monoatomic gas
B) \[{{C}_{V}}>\frac{3}{2}R\]for a monoatomic gas
C) \[{{C}_{V}}<\frac{5}{2}R\]for a diatomic gas
D) \[{{C}_{V}}=\frac{5}{2}R\]for a diatomic gas
Correct Answer: A
Solution :
At ordinary temperature, the vibrational kinetic energy of a monoatomic gas is zero. So, \[{{C}_{V}}=\frac{3}{2}R\] The value is same for high temperature also. In case of diatomic gas \[{{C}_{V}}=\frac{5}{2}R\](at low temperature) Also, \[{{C}_{V}}>\frac{5}{2}R\](at high temperature due to vibrational kinetic energy)You need to login to perform this action.
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