question_answer

\[{{I}_{2}}+2{{S}_{2}}O_{3}^{2-}\xrightarrow{{}}{{S}_{2}}O_{6}^{2-}+2{{I}^{-}}\] In the above reaction

A)  iodine is reduced; sulphur is reduced

B)  iodine is reduced; sulphur is oxidized

C)  iodine is oxidised; sulphur is reduced

D)  iodine is oxidised; sulphur is oxidized

Correct Answer: B

Solution :

Increase in oxidation number is oxidation while decrease in oxidation number represents reduction.