A) favours the formation of\[{{N}_{2}}{{O}_{4}}\]
B) favours the decomposition of\[{{N}_{2}}{{O}_{4}}\]
C) does not affect equilibrium
D) stop the reaction
Correct Answer: B
Solution :
The given reaction is exothermic and according to Le-Chatelier principle high temperature shifts the equilibrium in backward direction. In other words, high temperature favours the decomposition of\[{{N}_{2}}{{O}_{4}}\].
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