A) \[8.46T\]
B) \[3.33T\]
C) \[8.64\times {{10}^{-2}}T\]
D) None of these
Correct Answer: B
Solution :
To keep the particle moving in horizontal direction\[{{F}_{B}}\]should be equal to weight or\[qvB=mg\] [For minimum value of\[B\]angle between\[\mathbf{\vec{v}}\]and\[\overrightarrow{\mathbf{B}}\]has to be\[\frac{\pi }{2}\]] \[\Rightarrow \] \[B=\frac{0.5\times {{10}^{-3}}\times 10}{2.5\times {{10}^{-8}}\times 6\times {{10}^{4}}}=3.33T\]You need to login to perform this action.
You will be redirected in
3 sec