A) nitrobenzene
B) methylamine
C) nitromethane
D) nitro sobenzene
Correct Answer: A
Solution :
\[\underset{A}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,\xrightarrow[Sn/Cl]{\operatorname{Re}d}\underset{B}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,\xrightarrow[CHC{{l}_{3}}]{KOH}\underset{C}{\mathop{{{C}_{6}}{{H}_{5}}NC}}\,\] \[\xrightarrow[Boil]{{{H}_{2}}O}\underset{aniline}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+HCOOH\] Hence, the compound A is nitrobenzene.You need to login to perform this action.
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