A) \[\frac{p}{2\mu mg}\]
B) \[\frac{{{p}^{2}}}{2\mu mg}\]
C) \[\frac{p}{2\mu {{m}^{2}}g}\]
D) \[\frac{{{p}^{2}}}{2\mu {{m}^{2}}g}\]
Correct Answer: D
Solution :
Stopping distance\[s=\frac{{{u}^{2}}}{2\mu g}=\frac{{{m}^{2}}{{u}^{2}}}{2\mu g{{m}^{2}}}=\frac{{{p}^{2}}}{2\mu {{m}^{2}}g}\]You need to login to perform this action.
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