A) \[Cr{{O}_{2}}C{{l}_{2}}\]
B) \[C{{r}_{2}}{{O}_{3}}\]
C) \[CrC{{l}_{3}}\]
D) \[CrOC{{l}_{2}}\]
Correct Answer: A
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+4NaCl+6{{H}_{2}}S{{O}_{4}}\]\[\xrightarrow{{}}2KHS{{O}_{4}}+4NaHS{{O}_{4}}\] \[\underset{chromyl\,\,chloride}{\mathop{+2Cr{{O}_{2}}C{{l}_{2}}}}\,+3{{H}_{2}}O\]You need to login to perform this action.
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