A) It is paramagnetic due to the presence of 4 unpaired electrons
B) It has coordination number of 6
C) It is outer orbital complex
D) It involves\[{{d}^{2}}s{{p}^{3}}\]hybridisation
Correct Answer: D
Solution :
In\[{{[Co{{(F)}_{6}}]}^{3-}}\], \[Co\]is in\[+3\]oxidation state. \[{{[Co{{(F)}_{6}}]}^{3-}}\]is an outer orbital complex showing\[s{{p}^{3}}{{d}^{2}}\]hybridisation due to the presence of weak field ligand. It is paramagnetic due to the presence of four unpaired electrons.You need to login to perform this action.
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